2500=2x^2-50x

Solution for 2500=2x^2-50x equation:

2500=2x^2-50x

We move all terms to the left:

2500-(2x^2-50x)=0

We get rid of parentheses

-2x^2+50x+2500=0

a = -2; b = 50; c = +2500;
Δ = b2-4ac
Δ = 502-4·(-2)·2500
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-150}{2*-2}=\frac{-200}{-4}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+150}{2*-2}=\frac{100}{-4}
=-25
$